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Venus
Astronomical Enigma
Part 3
Venus Equation

Venus Equation

Let us suppose that we do not know the orbit of Venus.

We may assume we know the orbit of Earth, at unity, and the orbit of Mercury, at 0.3870987 AU.

We also know that orbits should be raised to the power (9/4p).

Earth, at unity, remains as unity when raised to any power.

Mercury becomes 0.506756171.

We do not know Venus, but we may call it 'V', and when raised to the power (9/4p) we may refer to it as V(9/4p) .

The following statement is true :-

{ [1 - V(9/4p) ] / [V(9/4p) - 0.506756171] } -V = 0.00

If we do not know the orbit of Venus, then we can use this expression to calculate it by successive approximation.

There is only one solution to this equation, and close examination reveals that the value of V is determined by the value of V. Venus determines its own orbit, or appears to.

The solution is .............. 0.723331002

Nortons figure for Venus is 0.7233322

The mean orbit of Venus in AU and the ratio b/a have the same numerical value.

Fig 7
Illustrating the problem of Venus
and the ratio b/a.
Venus = (b/a)

The possible range of the ratio b/a is from zero to infinity, depending on the orbit of Venus in relation to Mercury and Earth. Considering that there is no scientific reason for the planet Venus to exist at all, the probability that the ratio would turn out to be numerically the same as the orbit of Venus in astronomical units is infinitely small.

There is only one orbit where this condition can apply, and Venus 'just happens' to find itself in that unique orbit, with a precision which is hard to explain, (five digits, see fig 8).

Venus/Earth = (b/a)

Possible range, Venus and (b/a)

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